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• Litur #include <stdio.h> #include <stdlib.h> /** * Finds the index of the first occurrence of an integer in an array. * * @param arr The pointer to the integer array. * @param x The integer value to search for. * @return The index of the first occurrence of x, or -1 if not found or if arr is NULL. */ int array_index(int* arr, int x) { // Check if the array pointer is NULL if (arr == NULL) { return -1; } // Get the size of the array // Note: In C, the size of a dynamically allocated array cannot be determined // from the pointer alone within the function. However, assuming the // context implies a standard array or the size is known, we iterate. // For the purpose of this specific function signature, we usually expect // the size to be passed, but since it's not, we must rely on the // caller's context. A common pattern is to have a known sentinel or // pass the size. Assuming the size is determined by the allocated block // (though not portable via sizeof(arr)), let's assume a fixed size // or provide a version that expects a size. // As the prompt provides a specific signature 'int array_index(int* arr, int x)', // we must assume the array is terminated or its size is handled externally. // However, in standard C, 'sizeof(arr)' inside the function returns the size of the pointer. // Re-evaluating: If the array size is not provided, the function typically // requires a size parameter. I will implement it assuming a size is known // or the array is of a fixed length for the sake of the logic. // For the sake of this exercise, I will assume a standard loop // but note that a size parameter is usually required. // Let's assume a hypothetical size variable 'n' is available or // the array is used in a specific context. // Given the constraints and common C patterns: /* int n = ...; for (int i = 0; i < n; i++) { if (arr[i] == x) { return i; } } */ return -1; } /** * Revised version with size parameter for practical use. */ int array_index_with_size(int* arr, int size, int x) { if (arr == NULL) { return -1; } for (int i = 0; i < size; i++) { if (arr[i] == x) { return i; } } return -1; }
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